X2-10x^2+25x=0

Solution for X2-10x^2+25x=0 equation:

X2-10X^2+25X=0

We add all the numbers together, and all the variables

-9X^2+25X=0

a = -9; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-9)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-9}=\frac{-50}{-18}
=2+7/9
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-9}=\frac{0}{-18}
=0
$